36x^2+18x^2+6x=0

Solution for 36x^2+18x^2+6x=0 equation:

36x^2+18x^2+6x=0

We add all the numbers together, and all the variables

54x^2+6x=0

a = 54; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·54·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*54}=\frac{-12}{108}
=-1/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*54}=\frac{0}{108}
=0
$